Questions: The temperature T of a person during an iftiness is given by T(t)=10t/t^2+1+98.6, where T is the temperature, in degrees Fahrenheit, at time t, in hours.
(a) Find the rate of change of the temperature with respect to time.
(b) Find the temperature at t=1 hr.
(c) Find the rate of change of the temperature at t=1 hr.
Transcript text: The temperature T of a person during an iftiness is given by $T(t)=\frac{10 t}{t^{2}+1}+98.6$, where $T$ is the temperature, in degrees Fahrenheit, at time $t$, in hours.
(a) Find the rate of change of the temperature with respect to time.
(b) Find the temperature at $\mathrm{t}=1 \mathrm{hr}$.
(c) Find the rate of change of the temperature at $\mathrm{t}=1 \mathrm{hr}$.
Solution
Solution Steps
Step 1: Find the derivative of T(t)
To find the rate of change of the temperature with respect to time, we need to find the derivative of T(t) with respect to t.
T(t) = 10t/(t² + 1) + 98.6
Using the quotient rule for differentiation, the derivative of 10t/(t² + 1) is (10(t² + 1) - 10t(2t))/(t² + 1)² = (10t² + 10 - 20t²)/(t² + 1)² = (10 - 10t²)/(t² + 1)² = 10(1 - t²)/(t² + 1)²
Thus, T'(t) = 10(1 - t²)/(t² + 1)²
Step 2: Find the temperature at t = 1 hr
Substitute t = 1 into the equation for T(t):
T(1) = 10(1)/(1² + 1) + 98.6
T(1) = 10/2 + 98.6
T(1) = 5 + 98.6
T(1) = 103.6
Step 3: Find the rate of change of the temperature at t = 1 hr
Substitute t = 1 into the equation for T'(t):
T'(1) = 10(1 - 1²)/(1² + 1)²
T'(1) = 10(0)/2²
T'(1) = 0/4
T'(1) = 0