Questions: Solve: 3/4 y-6=2+1/4 y y=16 y=4 y=-8 y=8

Solution Steps

To solve the equation \(\frac{3}{4} y - 6 = 2 + \frac{1}{4} y\), we need to isolate \(y\). First, subtract \(\frac{1}{4} y\) from both sides to combine like terms. Then, add 6 to both sides to isolate the term with \(y\). Finally, solve for \(y\) by multiplying both sides by the reciprocal of the coefficient of \(y\).

We start with the equation: \[ \frac{3}{4} y - 6 = 2 + \frac{1}{4} y \]

To isolate \(y\), we first subtract \(\frac{1}{4} y\) from both sides: \[ \frac{3}{4} y - \frac{1}{4} y - 6 = 2 \] This simplifies to: \[ \frac{2}{4} y - 6 = 2 \] or \[ \frac{1}{2} y - 6 = 2 \]

Next, we add 6 to both sides: \[ \frac{1}{2} y = 8 \] Now, we multiply both sides by 2 to solve for \(y\): \[ y = 16 \]

Final Answer