Questions: Determine the equation of the line parallel to (y=2x+1) that goes through ((-5,3)).
Sketch (y=2x+1) and the parallel line through ((-5,3)) found in part 1.
Transcript text: Determine the equation of the line parallel to $\boldsymbol{y}=2 x+1$ that goes through $(-5,3)$.
Sketch $y=2 x+1$ and the parallel line through $(-5,3)$ found in part 1.
Solution
Solution Steps
Step 1: Identify the slope of the given line
The given line is \( y = 2x + 1 \). The slope-intercept form of a line is \( y = mx + b \), where \( m \) is the slope. Here, the slope \( m \) is 2.
Step 2: Use the point-slope form to find the equation of the parallel line
The point-slope form of a line is \( y - y_1 = m(x - x_1) \), where \( (x_1, y_1) \) is a point on the line and \( m \) is the slope. We have the point \((-5, 3)\) and the slope \( m = 2 \).
Substitute the values into the point-slope form:
\[ y - 3 = 2(x + 5) \]
Step 3: Simplify the equation to slope-intercept form
Distribute and simplify the equation:
\[ y - 3 = 2x + 10 \]
\[ y = 2x + 13 \]
Final Answer
The equation of the line parallel to \( y = 2x + 1 \) that goes through the point \((-5, 3)\) is \( y = 2x + 13 \).