Questions: Determine the equation of the line parallel to (y=2x+1) that goes through ((-5,3)). Sketch (y=2x+1) and the parallel line through ((-5,3)) found in part 1.

Determine the equation of the line parallel to (y=2x+1) that goes through ((-5,3)).

Sketch (y=2x+1) and the parallel line through ((-5,3)) found in part 1.
Transcript text: Determine the equation of the line parallel to $\boldsymbol{y}=2 x+1$ that goes through $(-5,3)$. Sketch $y=2 x+1$ and the parallel line through $(-5,3)$ found in part 1.
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Solution

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Solution Steps

Step 1: Identify the slope of the given line

The given line is \( y = 2x + 1 \). The slope-intercept form of a line is \( y = mx + b \), where \( m \) is the slope. Here, the slope \( m \) is 2.

Step 2: Use the point-slope form to find the equation of the parallel line

The point-slope form of a line is \( y - y_1 = m(x - x_1) \), where \( (x_1, y_1) \) is a point on the line and \( m \) is the slope. We have the point \((-5, 3)\) and the slope \( m = 2 \).

Substitute the values into the point-slope form: \[ y - 3 = 2(x + 5) \]

Step 3: Simplify the equation to slope-intercept form

Distribute and simplify the equation: \[ y - 3 = 2x + 10 \] \[ y = 2x + 13 \]

Final Answer

The equation of the line parallel to \( y = 2x + 1 \) that goes through the point \((-5, 3)\) is \( y = 2x + 13 \).

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