Questions: Given the function g(n)=(n-2)(n+6)(n-7) :
the coordinates of its g-intercept are
the coordinates of its n-intercepts are
Transcript text: Given the function $g(n)=(n-2)(n+6)(n-7)$ :
the coordinates of its $g$-intercept are $\square$
the coordinates of its $n$-intercepts are $\square$
Solution
Solution Steps
Solution Approach
To find the coordinates of the \( g \)-intercept of the function \( g(n) = (n-2)(n+6)(n-7) \), we need to evaluate the function at \( n = 0 \). This will give us the \( g \)-intercept, which is the point where the graph of the function crosses the \( g \)-axis. For the \( n \)-intercepts, we need to find the values of \( n \) that make the function equal to zero. These are the roots of the polynomial, which can be found by setting each factor equal to zero.
Step 1: Calculate the \( g \)-intercept
To find the \( g \)-intercept, we evaluate the function at \( n = 0 \):
\[
g(0) = (0 - 2)(0 + 6)(0 - 7) = (-2)(6)(-7) = 84
\]
Thus, the coordinates of the \( g \)-intercept are \( (0, 84) \).
Step 2: Find the \( n \)-intercepts
The \( n \)-intercepts occur where the function equals zero:
\[
g(n) = (n - 2)(n + 6)(n - 7) = 0
\]
Setting each factor to zero gives us the solutions:
\( n - 2 = 0 \) → \( n = 2 \)
\( n + 6 = 0 \) → \( n = -6 \)
\( n - 7 = 0 \) → \( n = 7 \)
Thus, the coordinates of the \( n \)-intercepts are \( (-6, 0) \), \( (2, 0) \), and \( (7, 0) \).
Final Answer
The coordinates of the \( g \)-intercept are \( \boxed{(0, 84)} \) and the coordinates of the \( n \)-intercepts are \( \boxed{(-6, 0), (2, 0), (7, 0)} \).