Questions: Solve for (y) in terms of (t). [ ln (y-43)=4 t ]

Solve for (y) in terms of (t).
[
ln (y-43)=4 t
]
Transcript text: Solve for $y$ in terms of $t$. \[ \ln (y-43)=4 t \]
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Solution

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Solution Steps

To solve for \( y \) in terms of \( t \) from the equation \(\ln(y - 43) = 4t\), we need to isolate \( y \). We can do this by exponentiating both sides to eliminate the natural logarithm, and then solving for \( y \).

Step 1: Understand the Problem

We are given the equation:

\[ \ln (y-43) = 4t \]

Our task is to solve for \( y \) in terms of \( t \).

Step 2: Isolate the Exponential Expression

To solve for \( y \), we need to eliminate the natural logarithm. We do this by exponentiating both sides of the equation. Recall that if \(\ln(a) = b\), then \(a = e^b\).

\[ y - 43 = e^{4t} \]

Step 3: Solve for \( y \)

Now, we solve for \( y \) by adding 43 to both sides of the equation:

\[ y = e^{4t} + 43 \]

Final Answer

The solution for \( y \) in terms of \( t \) is:

\[ \boxed{y = e^{4t} + 43} \]

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