Questions: Listed below are the amounts of net worth (in millions of dollars) of the ten wealthiest celebrities in a country. Construct a 90% confidence interval. What does the result tell us about the population of all celebrities? Do the data appear to be from a normally distributed population as required? 240 194 181 159 157 156 148 148 148 148 What is the confidence interval estimate of the population mean μ ? million < μ < million (Round to one decimal place as needed.)

Listed below are the amounts of net worth (in millions of dollars) of the ten wealthiest celebrities in a country. Construct a 90% confidence interval. What does the result tell us about the population of all celebrities? Do the data appear to be from a normally distributed population as required?

240
194
181
159
157
156
148
148
148
148

What is the confidence interval estimate of the population mean μ ?
 million < μ <  million
(Round to one decimal place as needed.)
Transcript text: Listed below are the amounts of net worth (in millions of dollars) of the ten wealthiest celebrities in a country. Construct a 90\% confidence interval. What does the result tell us about the population of all celebrities? Do the data appear to be from a normally distributed population as required? 240 194 181 159 157 156 148 148 148 148 What is the confidence interval estimate of the population mean $\mu$ ? $\$ \square$ $\square$ million $<\mu<\$$ $\square$ million (Round to one decimal place as needed.)
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Solution

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Solution Steps

Step 1: Calculate the Mean

The mean net worth of the ten wealthiest celebrities is calculated as follows:

\[ \mu = \frac{\sum_{i=1}^{N} x_i}{N} = \frac{1679}{10} = 167.9 \]

Step 2: Calculate the Sample Standard Deviation

The sample standard deviation is calculated using the formula:

\[ s = \sqrt{\frac{\sum (x_i - \mu)^2}{n-1}} = \sqrt{886.1} = 29.8 \]

Step 3: Construct the 90% Confidence Interval

To construct the 90% confidence interval for the population mean, we use the formula:

\[ \bar{x} \pm t \frac{s}{\sqrt{n}} \]

Where:

  • \(\bar{x} = 167.9\) (sample mean)
  • \(t \approx 1.8\) (t-value for 90% confidence level with \(n-1 = 9\) degrees of freedom)
  • \(s = 29.8\) (sample standard deviation)
  • \(n = 10\) (sample size)

Calculating the confidence interval:

\[ 167.9 \pm 1.8 \cdot \frac{29.8}{\sqrt{10}} = (150.6, 185.2) \]

Final Answer

The 90% confidence interval for the population mean \(\mu\) is:

\[ \boxed{(150.6, 185.2)} \]

This interval suggests that we can be 90% confident that the true mean net worth of all celebrities in the population falls within this range.

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