Questions: Solve the following systems of equations for the unknown variables. Enter your answer in (x, y) format.
6 x+3 y=18
5 x+y=12
Transcript text: Solve the following systems of equations for the unknown variables. Enter your answer in $(x, y)$ format.
\[
\begin{array}{l}
6 x+3 y=18 \\
5 x+y=12
\end{array}
\]
Solution
Solution Steps
Step 1: Formulate the Augmented Matrix
We start with the system of equations:
\[
\begin{array}{l}
6x + 3y = 18 \\
5x + y = 12
\end{array}
\]
We can represent this system in augmented matrix form \( [A | b] \):
\[
\left[ A | b \right] = \left[ \begin{array}{ccc}
6 & 3 & 18 \\
5 & 1 & 12 \\
\end{array} \right]
\]
Step 2: Row Reduction
Next, we perform row operations to simplify the augmented matrix. We can start by dividing the first row by 6:
\[
\left[ A | b \right] = \left[ \begin{array}{ccc}
1 & \frac{1}{2} & 3 \\
5 & 1 & 12 \\
\end{array} \right]
\]
Then, we eliminate the first variable from the second row by subtracting 5 times the first row from the second row:
\[
\left[ A | b \right] = \left[ \begin{array}{ccc}
1 & \frac{1}{2} & 3 \\
0 & -\frac{3}{2} & -3 \\
\end{array} \right]
\]
Step 3: Continue Row Reduction
Next, we can simplify the second row by multiplying it by \(-\frac{2}{3}\):
\[
\left[ A | b \right] = \left[ \begin{array}{ccc}
1 & \frac{1}{2} & 3 \\
0 & 1 & 2 \\
\end{array} \right]
\]
Step 4: Back Substitution
Now, we can eliminate the second variable from the first row by subtracting \(\frac{1}{2}\) times the second row from the first row:
\[
\left[ A | b \right] = \left[ \begin{array}{ccc}
1 & 0 & 2 \\
0 & 1 & 2 \\
\end{array} \right]
\]
Step 5: Extract the Solutions
From the final augmented matrix, we can read the solutions directly:
\[
x = 2, \quad y = 2
\]