Questions: Find the area of the figure.

Solution Steps

The figure can be divided into three rectangles and two triangles. Two rectangles are on the sides, and the center one is formed by a dashed line. The triangles are formed above and below the center rectangle.

The two similar rectangles have dimensions 96 ft by 96 ft. Their combined area is $2 * (96 * 96) = 18432\text{ ft}^2$. The center rectangle has dimensions 93 ft by 96 ft, giving an area of $93 * 96 = 8928 \text{ ft}^2$.

The two triangles are congruent and each has a base of 96 ft and a height of $\frac{96 - 93}{2} = \frac{3}{2} = 1.5$ ft. Therefore, the area of each triangle is $\frac{1}{2} * 96 * 1.5 = 72\text{ ft}^2$. Their combined area is $2 * 72 = 144\text{ ft}^2$.

The total area of the figure is the sum of the areas of the rectangles and the triangles: $18432 + 8928 + 144 = 27504\text{ ft}^2$.

Final Answer: The final answer is $\boxed{27504}$