Questions: Next, the chemist measures the volume of the unknown liquid as 0.850 L and the mass of the unknown liquid as 600 g. Calculate the density of the liquid. Be sure your answer has the correct number of significant digits. g / cm^3 Given the data above, is it possible to identify the liquid? - yes - no - pentane - chloroform - diethylamine - ethanolamine - carbon tetrachloride

Solution Steps

Density is calculated using the formula:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

Given:

• Mass = 600 g
• Volume = 0.850 L

First, convert the volume from liters to cubic centimeters (cm\(^3\)) since 1 L = 1000 cm\(^3\):

\[ 0.850 \, \text{L} = 0.850 \times 1000 \, \text{cm}^3 = 850 \, \text{cm}^3 \]

Now, calculate the density:

\[ \text{Density} = \frac{600 \, \text{g}}{850 \, \text{cm}^3} = 0.7059 \, \text{g/cm}^3 \]

To determine if the liquid can be identified, we compare the calculated density with known densities of the given substances. The density of the liquid is approximately 0.7059 g/cm\(^3\).

• Pentane: ~0.626 g/cm\(^3\)
• Chloroform: ~1.489 g/cm\(^3\)
• Diethylamine: ~0.707 g/cm\(^3\)
• Ethanolamine: ~1.012 g/cm\(^3\)
• Carbon tetrachloride: ~1.594 g/cm\(^3\)

The calculated density is closest to the density of diethylamine.

Final Answer