Questions: Below is the curve r=1-sin(θ) for 0 ≤ θ ≤ a. Adjust the value of a using the slider provided to complete the graph.

Below is the curve r=1-sin(θ) for 0 ≤ θ ≤ a. Adjust the value of a using the slider provided to complete the graph.
Transcript text: Below is the curve $r=1-\sin (\theta)$ for $0 \leq \theta \leq a$. Adjust the value of $a$ using the slider provided to complete the graph.
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Solution

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Solution Steps

Step 1: Analyze the graph

The graph shows a polar curve with the equation \(r = 1 - \sin(\theta)\). The graph is drawn from \(\theta = 0\) to some angle \(a\). The radial lines are in increments of \(\pi/6\). The circles are in increments of 1. We are given \(a = 0.40\). The graph currently shows a small portion of the curve in red, starting at \(\theta=0\) and extending slightly.

Step 2: Convert \(a\) to radians

The angle \(a\) is given as 0.40, which is likely in radians. The red portion in the graph spans an angle slightly past the 0 radian mark. This visually corresponds to approximately 0.40 radians.

Step 3: Determine the correct value of \(a\)

To complete the graph of \(r = 1 - \sin(\theta)\), we need the angle to go from 0 to \(2\pi\). So, we must set \(a = 2\pi\).

Final Answer

\(\boxed{a = 2\pi}\)

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