The calculated degrees of freedom total is \(11\), the calculated sum of squares total is \(83\), and the hypotheses are:
- \(H_0: \mu_1 = \mu_2 = \mu_3\)
- \(H_1: \text{At least one } \mu_i \text{ is different}\)
Thus, the final answer is:
\[
\boxed{H_0: \text{All the means are equal; } H_1: \text{Not all the means are equal.}}
\]