To solve the equation \( |4x - 1| = 2x + 13 \), we need to consider two cases due to the absolute value:
- \( 4x - 1 = 2x + 13 \)
- \( 4x - 1 = -(2x + 13) \)
For each case, solve for \( x \) and check if the solutions satisfy the original equation.
To solve the equation \( |4x - 1| = 2x + 13 \), we need to consider two cases due to the absolute value:
- \( 4x - 1 = 2x + 13 \)
- \( 4x - 1 = -(2x + 13) \)
For the first case, solve the equation:
\[ 4x - 1 = 2x + 13 \]
Subtract \( 2x \) from both sides:
\[ 2x - 1 = 13 \]
Add 1 to both sides:
\[ 2x = 14 \]
Divide by 2:
\[ x = 7 \]
For the second case, solve the equation:
\[ 4x - 1 = -(2x + 13) \]
Distribute the negative sign:
\[ 4x - 1 = -2x - 13 \]
Add \( 2x \) to both sides:
\[ 6x - 1 = -13 \]
Add 1 to both sides:
\[ 6x = -12 \]
Divide by 6:
\[ x = -2 \]
Verify each solution by substituting back into the original equation:
Both solutions satisfy the original equation.