Questions: Multiply: (-3+2 i)(5-i) -17+13 i 2+i 13-13 i -13+13 i

Multiply: (-3+2 i)(5-i)
-17+13 i
2+i
13-13 i
-13+13 i
Transcript text: Multiply: $(-3+2 i)(5-i)$ $-17+13 i$ $2+i$ $13-13 i$ $-13+13 i$
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Solution

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Solution Steps

To multiply two complex numbers, use the distributive property (also known as the FOIL method for binomials). Multiply each part of the first complex number by each part of the second complex number, and then combine like terms. Remember that \(i^2 = -1\).

Step 1: Identify the Complex Numbers

We are given two complex numbers: \((-3 + 2i)\) and \((5 - i)\).

Step 2: Apply the Distributive Property

To multiply these complex numbers, we use the distributive property: \[ (-3 + 2i)(5 - i) = (-3) \cdot 5 + (-3) \cdot (-i) + (2i) \cdot 5 + (2i) \cdot (-i) \]

Step 3: Perform the Multiplication

Calculate each term:

  • \((-3) \cdot 5 = -15\)
  • \((-3) \cdot (-i) = 3i\)
  • \((2i) \cdot 5 = 10i\)
  • \((2i) \cdot (-i) = -2i^2\)
Step 4: Simplify Using \(i^2 = -1\)

Since \(i^2 = -1\), we have: \[ -2i^2 = -2(-1) = 2 \]

Step 5: Combine Like Terms

Combine the real and imaginary parts: \[ -15 + 3i + 10i + 2 = (-15 + 2) + (3i + 10i) = -13 + 13i \]

Final Answer

\(\boxed{-13 + 13i}\)

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