To find the probability \( P(X < 12) \) for a uniform distribution \( U(0, 50) \), we use the formula for the probability of a uniform distribution:
\[
P(X < x) = \frac{x - a}{b - a}
\]
where \( a = 0 \) and \( b = 50 \). Substituting \( x = 12 \):
\[
P(X < 12) = \frac{12 - 0}{50 - 0} = \frac{12}{50} = 0.24
\]
Thus, the probability is \( 0.24 \).
To find the probability \( P(X > 800) \) for a uniform distribution \( U(0, 1000) \), we can use the complementary probability:
\[
P(X > x) = 1 - P(X < x)
\]
Calculating \( P(X < 800) \):
\[
P(X < 800) = \frac{800 - 0}{1000 - 0} = \frac{800}{1000} = 0.8
\]
Thus,
\[
P(X > 800) = 1 - 0.8 = 0.2
\]
The probability is \( 0.2 \).
To find the probability \( P(26 < X < 58) \) for a uniform distribution \( U(19, 63) \), we use the formula:
\[
P(a < X < b) = \frac{b - a}{d - c}
\]
where \( c = 19 \) and \( d = 63 \). Substituting \( a = 26 \) and \( b = 58 \):
\[
P(26 < X < 58) = \frac{58 - 26}{63 - 19} = \frac{32}{44} = \frac{8}{11} \approx 0.7273
\]
Thus, the probability is approximately \( 0.7273 \).
- For \( P(X < 12) \) for \( U(0, 50) \): \( \boxed{0.24} \)
- For \( P(X > 800) \) for \( U(0, 1000) \): \( \boxed{0.2} \)
- For \( P(26 < X < 58) \) for \( U(19, 63) \): \( \boxed{0.7273} \)