Questions: Convert the equation (f(t)=253 e^-0.27 t) to the form (f(t)=a b^t)
a=
b=
Transcript text: Convert the equation $f(t)=253 e^{-0.27 t}$ to the form $f(t)=a b^{t}$
\[
\begin{array}{l}
a= \\
b=
\end{array}
\]
Solution
Solution Steps
Step 1: Identify the initial value \(a\)
The initial value \(a\) is the coefficient in front of the exponential term in the given function \(f(t) = 253 e^{-0.27 t}\). Therefore, we have:
\[
a = 253
\]
Step 2: Determine the new base \(b\)
To find the new base \(b\), we need to rewrite the exponent's base \(e\) to the power of the decay rate as a single number. This can be done by evaluating \(e^{-0.27}\):
\[
b = e^{-0.27} \approx 0.7634
\]
Final Answer
The equation \(f(t) = 253 e^{-0.27 t}\) can be converted to the form \(f(t) = a b^t\) with:
\[
\begin{array}{l}
a = 253 \\
b \approx 0.7634
\end{array}
\]
\[
\boxed{a = 253, \, b \approx 0.7634}
\]