To solve the given function \( f(h) = \frac{16(2+h)^{2} - 64}{h} \), we need to simplify the expression. The approach involves expanding the squared term, simplifying the numerator, and then dividing by \( h \).
Step 1: Expand the Squared Term
First, we expand the squared term in the numerator of the function \( f(h) = \frac{16(2+h)^{2} - 64}{h} \). The expression \( (2+h)^{2} \) expands to \( 4 + 4h + h^{2} \).
Step 2: Simplify the Numerator
Substitute the expanded form into the numerator:
\[
16(4 + 4h + h^{2}) - 64
\]
This simplifies to:
\[
64 + 64h + 16h^{2} - 64
\]
Further simplification gives:
\[
16h^{2} + 64h
\]
Step 3: Divide by \( h \)
Now, divide the simplified numerator by \( h \):
\[
\frac{16h^{2} + 64h}{h} = 16h + 64
\]