Questions: Determine whether or not the mixing of each pair of solutions results in a buffer. 150.0 mL of 0.15 M HCl; 135.0 mL 155.0 mL of 0.15 M NH3; 155.0 mL of 0.10 M HCl 225.0 mL of 0.10 M NH3; 250.0 mL of 0.135 M NaOH 155.0 mL of 0.15 M NH3; 175.0 mL of 0.17 M HCl

Determine whether or not the mixing of each pair of solutions results in a buffer.

150.0 mL of 0.15 M HCl; 135.0 mL

155.0 mL of 0.15 M NH3; 155.0 mL of 0.10 M HCl

225.0 mL of 0.10 M NH3; 250.0 mL of 0.135 M NaOH

155.0 mL of 0.15 M NH3; 175.0 mL of 0.17 M HCl
Transcript text: Determine whether or not the mixing of each pair of solutions results in a buffer. 150.0 mL of $0.15 \mathrm{M} \mathrm{HCl} ; 135.0 \mathrm{~mL}$ 155.0 mL of $0.15 \mathrm{M} \mathrm{NH}_{3} ; 155.0$ mL of 0.10 MHCl 225.0 mL of $0.10 \mathrm{M} \mathrm{NH}_{3} ; 250.0$ mL of $0.135 M \mathrm{NaOH}$ 155.0 mL of $0.15 \mathrm{MHH}_{3} ; 175.0$ mL of 0.17 MHCl
failed

Solution

failed
failed

Solution Steps

Step 1: Identify the components of a buffer solution

A buffer solution typically consists of a weak acid and its conjugate base, or a weak base and its conjugate acid. The purpose of a buffer is to resist changes in pH when small amounts of acid or base are added.

Step 2: Analyze each pair of solutions
  1. 150.0 mL of 0.15 M HCl; 135.0 mL of 0.15 M NH\(_3\):

    • HCl is a strong acid.
    • NH\(_3\) is a weak base.
    • Mixing a strong acid with a weak base does not result in a buffer solution.
  2. 155.0 mL of 0.15 M NH\(_3\); 155.0 mL of 0.10 M HCl:

    • NH\(_3\) is a weak base.
    • HCl is a strong acid.
    • The moles of NH\(_3\) are \(0.155 \times 0.15 = 0.02325\) moles.
    • The moles of HCl are \(0.155 \times 0.10 = 0.0155\) moles.
    • Since there is an excess of NH\(_3\) after neutralization, the solution will contain NH\(_4^+\) (conjugate acid) and NH\(_3\) (weak base), forming a buffer solution.
  3. 225.0 mL of 0.10 M NH\(_3\); 250.0 mL of 0.135 M NaOH:

    • NH\(_3\) is a weak base.
    • NaOH is a strong base.
    • Mixing a weak base with a strong base does not result in a buffer solution.
  4. 155.0 mL of 0.15 M NH\(_4\)Cl; 175.0 mL of 0.17 M HCl:

    • NH\(_4\)Cl provides NH\(_4^+\) (conjugate acid of NH\(_3\)).
    • HCl is a strong acid.
    • Mixing a strong acid with the conjugate acid of a weak base does not result in a buffer solution.

Final Answer

  • Buffer solution: 155.0 mL of 0.15 M NH\(_3\); 155.0 mL of 0.10 M HCl
  • Not a buffer solution: 150.0 mL of 0.15 M HCl; 135.0 mL of 0.15 M NH\(_3\), 225.0 mL of 0.10 M NH\(_3\); 250.0 mL of 0.135 M NaOH, 155.0 mL of 0.15 M NH\(_4\)Cl; 175.0 mL of 0.17 M HCl
Was this solution helpful?
failed
Unhelpful
failed
Helpful