Questions: College CollegeName City StateCode Enrollment Bowdoin Brunswick ME 1828 Emory Atlanta GA 14769 Tufts Medford MA 10872 Rice Houston TX 6740 State StateCode StateName CapitalCity ME Maine Augusta TX Texas Austin MA Massachusetts Boston GA Georgia Atlanta Complete the following relational algebra expression to generate the Result table: Π(CollegeName, StateName) σ((A-))(College Φ((B-)) State) Result CollegeName StateName Bowdoin Maine

College
CollegeName  City  StateCode  Enrollment
Bowdoin  Brunswick  ME  1828
Emory  Atlanta  GA  14769
Tufts  Medford  MA  10872
Rice  Houston  TX  6740

State
StateCode  StateName  CapitalCity
ME  Maine  Augusta
TX  Texas  Austin
MA  Massachusetts  Boston
GA  Georgia  Atlanta

Complete the following relational algebra expression to generate the Result table:
Π(CollegeName, StateName) σ((A-))(College Φ((B-)) State)

Result
CollegeName  StateName
Bowdoin  Maine
Transcript text: College \begin{tabular}{|c|c|c|c|} \hline CollegeName & City & StateCode & Enrollment \\ \hline Bowdoin & Brunswick & ME & 1828 \\ \hline Emory & Atlanta & GA & 14769 \\ \hline Tufts & Medford & MA & 10872 \\ \hline Rice & Houston & TX & 6740 \\ \hline \end{tabular} State \begin{tabular}{|l|l|l|} \hline StateCode & \multicolumn{1}{|c|}{ StateName } & CapitalCity \\ \hline ME & Maine & Augusta \\ \hline TX & Texas & Austin \\ \hline MA & Massachusetts & Boston \\ \hline GA & Georgia & Atlanta \\ \hline \end{tabular} Complete the following relational algebra expression to generate the Result table: \[ \Pi_{(\text {CollegeName, StateName })} \sigma_{\left(\mathbf{A}_{-}\right)}\left(\text {College } \Phi_{\left(\mathbf{B}_{-}\right)} \text {State }\right) \] Result \begin{tabular}{|c|c|} \hline CollegeName & StateName \\ \hline Bowdoin & Maine \\ \hline \end{tabular}
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Solution

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To complete the relational algebra expression to generate the Result table, we need to understand the requirements and the given data.

Given Data:
  1. College Table:

    | CollegeName | City      | StateCode | Enrollment |
    |-------------|-----------|-----------|------------|
    | Bowdoin     | Brunswick | ME        | 1828       |
    | Emory       | Atlanta   | GA        | 14769      |
    | Tufts       | Medford   | MA        | 10872      |
    | Rice        | Houston   | TX        | 6740       |
    
  2. State Table:

    | StateCode | StateName      | CapitalCity |
    |-----------|----------------|-------------|
    | ME        | Maine          | Augusta     |
    | TX        | Texas          | Austin      |
    | MA        | Massachusetts  | Boston      |
    | GA        | Georgia        | Atlanta     |
    
  3. Result Table:

    | CollegeName | StateName |
    |-------------|-----------|
    | Bowdoin     | Maine     |
    
Relational Algebra Expression:

We need to generate a table with CollegeName and StateName where the CollegeName is "Bowdoin".

Steps to Derive the Expression:
  1. Join the College and State tables on StateCode: \[ \text{College} \bowtie_{\text{College.StateCode} = \text{State.StateCode}} \text{State} \]

  2. Select the row where CollegeName is "Bowdoin": \[ \sigma_{\text{CollegeName} = 'Bowdoin'} \]

  3. Project the required columns CollegeName and StateName: \[ \Pi_{\text{CollegeName, StateName}} \]

Complete Relational Algebra Expression:

\[ \Pi_{\text{CollegeName, StateName}} \sigma_{\text{CollegeName} = 'Bowdoin'} (\text{College} \bowtie_{\text{College.StateCode} = \text{State.StateCode}} \text{State}) \]

Explanation:
  • Join Operation (\(\bowtie\)): Combines the College and State tables based on the matching StateCode.
  • Selection Operation (\(\sigma\)): Filters the rows to include only those where CollegeName is "Bowdoin".
  • Projection Operation (\(\Pi\)): Selects only the CollegeName and StateName columns for the final result.
Summary:

The complete relational algebra expression to generate the Result table is: \[ \Pi_{\text{CollegeName, StateName}} \sigma_{\text{CollegeName} = 'Bowdoin'} (\text{College} \bowtie_{\text{College.StateCode} = \text{State.StateCode}} \text{State}) \]

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