Transcript text: The dot product of two vectors $\mathbf{u}=a_{1} \mathbf{i}+b_{1} \mathbf{j}$ and $\mathbf{v}=a_{2} \mathbf{i}+b_{2} \mathbf{j}$ is defined as $\mathbf{u} \cdot \mathbf{v}=a_{1} \cdot a_{2}+b_{1} \cdot b_{2}$.
Question: How much is $(3 \mathbf{i}+2 \mathbf{j}) \cdot(7 \mathbf{i}-3 \mathbf{j})$ ?
Solution
Solution Steps
To find the dot product of two vectors, we multiply the corresponding components of the vectors and then sum these products. For the vectors \( \mathbf{u} = 3\mathbf{i} + 2\mathbf{j} \) and \( \mathbf{v} = 7\mathbf{i} - 3\mathbf{j} \), we calculate the dot product as follows: multiply the \( \mathbf{i} \) components (3 and 7) and the \( \mathbf{j} \) components (2 and -3), then add the results.
Step 1: Define the Vectors
We are given two vectors:
\[
\mathbf{u} = 3\mathbf{i} + 2\mathbf{j}
\]
\[
\mathbf{v} = 7\mathbf{i} - 3\mathbf{j}
\]
Step 2: Calculate the Dot Product
The dot product \( \mathbf{u} \cdot \mathbf{v} \) is calculated using the formula:
\[
\mathbf{u} \cdot \mathbf{v} = a_{1} \cdot a_{2} + b_{1} \cdot b_{2}
\]
Substituting the components:
\[
\mathbf{u} \cdot \mathbf{v} = (3)(7) + (2)(-3)
\]