Questions: States of Mritter Calculating volume percent composition 1 / 5 A 278. mL solution was made by mixing 50.5 mL of hexane, which has a density of 0.66 g / mL, and 236 . mL of chloroform, which has a density of 1.49 g / mL. Calculate the volume percent of hexane in this solution. Be sure your answer has the right number of significant digits. %(v / v)

Solution Steps

The total volume of the solution is the sum of the volumes of hexane and chloroform.

\[ V_{\text{total}} = V_{\text{hexane}} + V_{\text{chloroform}} \]

Given:

• \( V_{\text{hexane}} = 50.5 \, \text{mL} \)
• \( V_{\text{chloroform}} = 236 \, \text{mL} \)

\[ V_{\text{total}} = 50.5 \, \text{mL} + 236 \, \text{mL} = 286.5 \, \text{mL} \]

The volume percent of hexane is given by the formula:

\[ \text{Volume percent of hexane} = \left( \frac{V_{\text{hexane}}}{V_{\text{total}}} \right) \times 100\% \]

Substitute the values:

\[ \text{Volume percent of hexane} = \left( \frac{50.5 \, \text{mL}}{286.5 \, \text{mL}} \right) \times 100\% \]

Perform the division and multiplication:

\[ \text{Volume percent of hexane} = \left( \frac{50.5}{286.5} \right) \times 100\% \approx 17.63\% \]

Final Answer