Questions: Solve for (u). [ frac2u-5=frac63u-15-4 ] If there is more than one solution, separate them with commas. If there is no solution, click on "No solution".

Solve for (u).
[
frac2u-5=frac63u-15-4
]

If there is more than one solution, separate them with commas. If there is no solution, click on "No solution".
Transcript text: 4:01 PM Tue Jan 7 Done www-awu.aleks.com - Rational Expressions Solving a rationsl equation that simplifies to linear: Unilike binomial... Solve for $u$. \[ \frac{2}{u-5}=\frac{6}{3 u-15}-4 \] If there is more than one solution, separate them with commas. If there is no solution, click on "No solution". $\square$ \[ u=[ \] No solution 므․ Explanation Check
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Solution

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Solution Steps

Step 1: Simplifying the Equation

We start with the equation: \[ \frac{2}{u-5} = \frac{6}{3u-15} - 4 \] Notice that \(3u - 15\) can be factored as \(3(u - 5)\). Thus, we can rewrite the equation as: \[ \frac{2}{u-5} = \frac{6}{3(u-5)} - 4 \]

Step 2: Eliminating Fractions

To eliminate the fractions, we can multiply both sides of the equation by \(3(u - 5)\): \[ 3 \cdot 2 = 6 - 4 \cdot 3(u - 5) \] This simplifies to: \[ 6 = 6 - 12(u - 5) \]

Step 3: Solving for \(u\)

Rearranging the equation gives: \[ 6 = 6 - 12u + 60 \] This simplifies to: \[ 0 = -12u + 60 \] Solving for \(u\) yields: \[ 12u = 60 \implies u = 5 \]

Final Answer

However, substituting \(u = 5\) back into the original equation leads to a division by zero in the left-hand side, indicating that this value is not valid. Therefore, there are no solutions to the equation.

The final answer is: \[ \boxed{\text{No solution}} \]

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