Questions: Part A For a species with a haploid number of 23 chromosomes, how many different combinations of maternal and paternal chromosomes are possible for the gametes based on the independent assortment of chromosomes during meiosis? 46 about 8 million 23 about 1,000 Submit Request Answer Provide Feedback Next ）

Part A For a species with a haploid number of 23 chromosomes, how many different combinations of maternal and paternal chromosomes are possible for the gametes based on the independent assortment of chromosomes during meiosis? 46 about 8 million 23 about 1,000 Submit Request Answer Provide Feedback Next ）
Transcript text: Part A For a species with a haploid number of 23 chromosomes, how many different combinations of maternal and paternal chromosomes are possible for the gametes based on the independent assortment of chromosomes during meiosis? 46 about 8 million 23 about 1,000 Submit Request Answer Provide Feedback Next ）
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Solution

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The answer is the second one: about 8 million.

Explanation:

  1. 46: This number is incorrect. It represents the diploid number of chromosomes in humans (2n), not the number of combinations.

  2. About 8 million: This is the correct answer. The number of different combinations of maternal and paternal chromosomes in gametes due to independent assortment is calculated using the formula \(2^n\), where \(n\) is the haploid number of chromosomes. For a species with a haploid number of 23, the calculation is \(2^{23}\), which is approximately 8.4 million.

  3. 23: This number is incorrect. It represents the haploid number of chromosomes, not the number of combinations.

  4. About 1,000: This number is incorrect. It is far less than the actual number of combinations possible.

In summary, the number of different combinations of maternal and paternal chromosomes possible for the gametes is about 8 million, based on the independent assortment of chromosomes during meiosis.

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