Questions: Determine the period of the following trigonometric function. y=-4 cos (8/5 x)-1

Determine the period of the following trigonometric function.
y=-4 cos (8/5 x)-1
Transcript text: Determine the period of the following trigonometric function. \[ y=-4 \cos \left(\frac{8}{5} x\right)-1 \]
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Solution

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Solution Steps

Step 1: Identify the Function Parameters

The given trigonometric function is

\[ y = -4 \cos\left(\frac{8}{5} x\right) - 1 \]

In this function, we can identify the parameters as follows:

  • Amplitude \( A = -4 \)
  • Horizontal scaling factor \( B = \frac{8}{5} \)
  • Horizontal shift \( C = 0 \)
  • Vertical shift \( D = -1 \)
Step 2: Calculate the Period

The period \( P \) of a cosine function is calculated using the formula:

\[ P = \frac{2\pi}{|B|} \]

Substituting the value of \( B \):

\[ P = \frac{2\pi}{\left|\frac{8}{5}\right|} = \frac{2\pi}{\frac{8}{5}} = \frac{2\pi \cdot 5}{8} = \frac{10\pi}{8} = \frac{5\pi}{4} \]

Step 3: Express the Period in Simplified Form

The period can also be expressed in terms of \( \pi \):

\[ P = 1.25\pi \]

Final Answer

The period of the function \( y = -4 \cos\left(\frac{8}{5} x\right) - 1 \) is

\[ \boxed{\frac{5\pi}{4}} \]

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