Questions: Determine whether each equation is balanced as written. Mg + H2 SO4 -> MgSO4 + H2 Balanced 2 HCl + Mg(OH)2 -> 2 H2 O + MgCl2 Not balanced AgNO3 + NaCl -> NaNO3 + AgCl Balanced H2 + O2 -> 2 H2 O choose... C6 H12 O6 + O2 -> 6 CO2 + 6 H2 O choose ... CH4 + O2 -> CO2 + H2 O Choose ...

Solution Steps

The first equation is: \[ \mathrm{Mg} + \mathrm{H}_{2}\mathrm{SO}_{4} \longrightarrow \mathrm{MgSO}_{4} + \mathrm{H}_{2} \]

• Reactants: 1 Mg, 2 H, 1 S, 4 O
• Products: 1 Mg, 2 H, 1 S, 4 O

Both sides have the same number of each type of atom, so the equation is balanced.

The second equation is: \[ 2 \mathrm{HCl} + \mathrm{Mg}(\mathrm{OH})_{2} \longrightarrow 2 \mathrm{H}_{2}\mathrm{O} + \mathrm{MgCl}_{2} \]

• Reactants: 2 H, 2 Cl, 1 Mg, 2 O
• Products: 4 H, 2 Cl, 1 Mg, 2 O

The number of hydrogen atoms is not balanced (2 on the reactant side and 4 on the product side). Therefore, the equation is not balanced.

The third equation is: \[ \mathrm{AgNO}_{3} + \mathrm{NaCl} \longrightarrow \mathrm{NaNO}_{3} + \mathrm{AgCl} \]

• Reactants: 1 Ag, 1 Na, 1 N, 3 O, 1 Cl
• Products: 1 Ag, 1 Na, 1 N, 3 O, 1 Cl

Both sides have the same number of each type of atom, so the equation is balanced.

Final Answer