Questions: toras AMt Thu dan 2 assignments.pennfoster.com Ieseon a Ixam Exam Lesson Name: States of Matter, Stoichiometry, and Phase Changes Exam number: 700634RR Exam Guidelines Exam Instructions Question 15 of 20 : Select the best answer for the question. 15. A gas in a 6.2 mL cylinder has a pressure of 1.4 atmospheres. A piston is pushed in until the gas volume is 3.1 mL , while the temperature remains constant. What's the final pressure of the gas in the cylinder? A. 5.6 atm B. 2.8 atm C. 4.8 atm D. 3.2 atm Mark for review (Will be highlighted on the review page) <<Previous Question Next Question >> Review My Answers Save

toras AMt Thu dan 2
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Ieseon a Ixam

Exam Lesson Name: States of Matter, Stoichiometry, and Phase Changes

Exam number: 700634RR
Exam Guidelines
Exam Instructions

Question 15 of 20 :
Select the best answer for the question.
15. A gas in a 6.2 mL cylinder has a pressure of 1.4 atmospheres. A piston is pushed in until the gas volume is 3.1 mL , while the temperature remains constant. What's the final pressure of the gas in the cylinder?
A. 5.6 atm
B. 2.8 atm
C. 4.8 atm
D. 3.2 atm
Mark for review (Will be highlighted on the review page)
<<Previous Question
Next Question >>
Review My Answers
Save
Transcript text: toras AMt Thu dan 2 assignments.pennfoster.com Ieseon a Ixam Exam Lesson Name: States of Matter, Stoichiometry, and Phase Changes Exam number: 700634RR Exam Guidelines Exam Instructions Question 15 of 20 : Select the best answer for the question. 15. A gas in a 6.2 mL cylinder has a pressure of 1.4 atmospheres. A piston is pushed in until the gas volume is 3.1 mL , while the temperature remains constant. What's the final pressure of the gas in the cylinder? A. 5.6 atm B. 2.8 atm C. 4.8 atm D. 3.2 atm Mark for review (Will be highlighted on the review page) <> Review My Answers Save \&
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Solution

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Solution Steps

Step 1: Identify the Given Information

We are given:

  • Initial volume, \( V_1 = 6.2 \, \text{mL} \)
  • Initial pressure, \( P_1 = 1.4 \, \text{atm} \)
  • Final volume, \( V_2 = 3.1 \, \text{mL} \)
  • The temperature remains constant.
Step 2: Apply Boyle's Law

Boyle's Law states that for a given mass of gas at constant temperature, the pressure of the gas is inversely proportional to its volume. Mathematically, this is expressed as: \[ P_1 V_1 = P_2 V_2 \]

Step 3: Solve for the Final Pressure

We need to find the final pressure \( P_2 \). Rearrange the equation to solve for \( P_2 \): \[ P_2 = \frac{P_1 V_1}{V_2} \]

Step 4: Substitute the Given Values

Substitute the given values into the equation: \[ P_2 = \frac{1.4 \, \text{atm} \times 6.2 \, \text{mL}}{3.1 \, \text{mL}} \]

Step 5: Calculate the Final Pressure

Perform the calculation: \[ P_2 = \frac{1.4 \times 6.2}{3.1} = \frac{8.68}{3.1} = 2.8 \, \text{atm} \]

Final Answer

The final pressure of the gas in the cylinder is \(\boxed{2.8 \, \text{atm}}\). The answer is B.

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