Questions: Determine the equivalent inductance if L4=24 H, L5=6 H, L6=16 H, L7=17 H, and L8=8 H.

Solution Steps

L4 and L5 are in parallel. The equivalent inductance is given by: $L_{45} = \frac{L_4 \cdot L_5}{L_4 + L_5} = \frac{24 \cdot 6}{24+6} = \frac{144}{30} = 4.8 H$

L7 and L8 are in series. The equivalent inductance is given by: $L_{78} = L_7 + L_8 = 17 + 8 = 25 H$

L6 and L78 are in parallel. The equivalent inductance is given by: $L_{678} = \frac{L_6 \cdot L_{78}}{L_6 + L_{78}} = \frac{16 \cdot 25}{16 + 25} = \frac{400}{41} H$

L45 and L678 are in series. The equivalent inductance is given by: $L_{eq} = L_{45} + L_{678} = 4.8 + \frac{400}{41} = 4.8 + 9.756 = 14.556 \approx 14.56 H $

Final Answer: The equivalent inductance is approximately 14.56 H.