Factor \( 625x^8 \) into its prime factors: \[ 625 = 5^4, \quad x^8 = x^{6} \cdot x^{2}. \] Thus, the expression becomes: \[ -7 \sqrt[3]{5^4 x^6 x^2}. \]
Extract the cube roots of the perfect cubes: \[ \sqrt[3]{5^4 x^6 x^2} = \sqrt[3]{5^3 \cdot 5 \cdot x^6 \cdot x^2} = 5x^2 \sqrt[3]{5x^2}. \]
Multiply the extracted terms with the coefficient \(-7\): \[ -7 \cdot 5x^2 \sqrt[3]{5x^2} = -35x^2 \sqrt[3]{5x^2}. \]
\(\boxed{-35x^2 \sqrt[3]{5x^2}}\)
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