Questions: Differentiate implicitly to find dy/dx. Then, find the slope of the curve at the given point.
2x^2 - y^2 = 8 ; (√5, √2)
dy/dx =
Transcript text: Differentiate implicitly to find $\frac{d y}{d x}$. Then, find the slope of the curve at the given point.
\[
\begin{array}{l}
2 x^{2}-y^{2}=8 ; \quad(\sqrt{5}, \sqrt{2}) \\
\frac{d y}{d x}=\square
\end{array}
\]
$\square$
Solution
Solution Steps
Step 1: Implicit Differentiation
We start with the equation given by the problem:
\[
2x^2 - y^2 = 8
\]
Differentiating both sides with respect to \(x\) gives:
\[
\frac{d}{dx}(2x^2) - \frac{d}{dx}(y^2) = 0
\]
This results in:
\[
4x - 2y \frac{dy}{dx} = 0
\]
Step 2: Solve for \(\frac{dy}{dx}\)
Rearranging the equation to isolate \(\frac{dy}{dx}\):
\[
2y \frac{dy}{dx} = 4x
\]
Dividing both sides by \(2y\):
\[
\frac{dy}{dx} = \frac{2x}{y}
\]
Step 3: Find the Slope at the Given Point
Now, we substitute the coordinates of the given point \((\sqrt{5}, \sqrt{2})\) into the derived formula for \(\frac{dy}{dx}\):