Questions: Given that g(x)=2x^2-3x+4, find each of the following. a) g(0) b) g(-1) c) g(3) d) g(-x) e) g(1-t) b) g(-1)=9 (Simplify your answer.) c) g(3)=13 (Simplify your answer.) d) g(-x)=2x^2+3x+4 (Simplify your answer.) e) g(1-t)= (Simplify your answer.)

Given that g(x)=2x^2-3x+4, find each of the following.
a) g(0)
b) g(-1)
c) g(3)
d) g(-x)
e) g(1-t)
b) g(-1)=9 (Simplify your answer.)
c) g(3)=13 (Simplify your answer.)
d) g(-x)=2x^2+3x+4 (Simplify your answer.)
e) g(1-t)= (Simplify your answer.)
Transcript text: Given that $g(x)=2 x^{2}-3 x+4$, find each of the following. a) $g(0)$ b) $g(-1)$ c) $g(3)$ d) $g(-x)$ e) $g(1-t)$ b) $g(-1)=9$ (Simplify your answer.) c) $g(3)=13$ (Simplify your answer.) d) $g(-x)=2 x^{2}+3 x+4$ (Simplify your answer.) e) $g(1-t)=$ $\square$ (Simplify your answer.)
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Solution

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Solution Steps

Step 1: Calculate \( g(0) \)

To find \( g(0) \), substitute \( x = 0 \) into the function \( g(x) = 2x^2 - 3x + 4 \): \[ g(0) = 2(0)^2 - 3(0) + 4 = 0 - 0 + 4 = 4. \] Thus, \( g(0) = 4 \).

Step 2: Calculate \( g(-1) \)

To find \( g(-1) \), substitute \( x = -1 \) into the function \( g(x) = 2x^2 - 3x + 4 \): \[ g(-1) = 2(-1)^2 - 3(-1) + 4 = 2(1) + 3 + 4 = 2 + 3 + 4 = 9. \] Thus, \( g(-1) = 9 \).

Step 3: Calculate \( g(3) \)

To find \( g(3) \), substitute \( x = 3 \) into the function \( g(x) = 2x^2 - 3x + 4 \): \[ g(3) = 2(3)^2 - 3(3) + 4 = 2(9) - 9 + 4 = 18 - 9 + 4 = 13. \] Thus, \( g(3) = 13 \).

Final Answer

\[ \boxed{ \begin{aligned} a) \quad g(0) &= 4, \\ b) \quad g(-1) &= 9, \\ c) \quad g(3) &= 13. \end{aligned} } \]

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