Questions: Given that g(x)=2x^2-3x+4, find each of the following.
a) g(0)
b) g(-1)
c) g(3)
d) g(-x)
e) g(1-t)
b) g(-1)=9 (Simplify your answer.)
c) g(3)=13 (Simplify your answer.)
d) g(-x)=2x^2+3x+4 (Simplify your answer.)
e) g(1-t)= (Simplify your answer.)
Transcript text: Given that $g(x)=2 x^{2}-3 x+4$, find each of the following.
a) $g(0)$
b) $g(-1)$
c) $g(3)$
d) $g(-x)$
e) $g(1-t)$
b) $g(-1)=9$ (Simplify your answer.)
c) $g(3)=13$ (Simplify your answer.)
d) $g(-x)=2 x^{2}+3 x+4$ (Simplify your answer.)
e) $g(1-t)=$ $\square$ (Simplify your answer.)
Solution
Solution Steps
Step 1: Calculate \( g(0) \)
To find \( g(0) \), substitute \( x = 0 \) into the function \( g(x) = 2x^2 - 3x + 4 \):
\[
g(0) = 2(0)^2 - 3(0) + 4 = 0 - 0 + 4 = 4.
\]
Thus, \( g(0) = 4 \).