Questions: A bag contains 19 blue, 28 purple, 21 red, and 29 orange balls. You pick one ball at random. Find the probability that it is not blue. P(not blue) =

A bag contains 19 blue, 28 purple, 21 red, and 29 orange balls. You pick one ball at random. Find the probability that it is not blue. P(not blue) =
Transcript text: A bag contains 19 blue, 28 purple, 21 red, and 29 orange balls. You pick one ball at random. Find the probability that it is not blue. \[ P(\text { not blue })= \] $\square$
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Solution

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Solution Steps

Step 1: Calculate the total number of balls in the bag, NN

Given the number of balls of each color: [19, 28, 21, 29], we sum these values to find the total number of balls in the bag, N=97N = 97.

Step 2: Identify the color(s) for which the probability is being calculated

The colors for which the probability is being calculated are indexed by [2, 3, 4] with respective counts 28, 21, 29. Thus, the sum of these counts, S=78S = 78.

Step 3: Calculate the probability

The probability, PP, is calculated as the ratio of SS to NN, i.e., P=SN=7897=0.8P = \frac{S}{N} = \frac{78}{97} = 0.8.

Final Answer: The probability of drawing a ball of the desired color(s) is 0.8.

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