Questions: √V min ≤ E 2/(2/6)

Transcript text: $\sqrt{V}$ min $\leqq$ E $\frac{2}{\frac{2}{6}}$

Solution

Solution Steps

Step 1: Identify the given information

The problem provides a rectangle with a given area of 144 square inches and asks for the width of the rectangle.

Step 2: Set up the equation

The area of a rectangle is given by the formula: \[ \text{Area} = \text{Length} \times \text{Width} \] Given that the area is 144 square inches, we can write: \[ 144 = \text{Length} \times \text{Width} \]

Step 3: Solve for the width

Assuming the length is given or can be determined, we can solve for the width. If the length is not provided, we need additional information to solve the problem. For now, let's assume the length is $ L $: \[ \text{Width} = \frac{144}{L} \]

Final Answer

The width of the rectangle is $ \frac{144}{L} $ inches, where $ L $ is the length of the rectangle.

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