Questions: A sample of size n=38 is drawn from a population whose standard deviation is σ=44. Find the margin of error for a 90% confidence interval for μ. Round the answer to at least three decimal places. The margin of error for a 90% confidence interval for μ is

A sample of size n=38 is drawn from a population whose standard deviation is σ=44. Find the margin of error for a 90% confidence interval for μ. Round the answer to at least three decimal places.

The margin of error for a 90% confidence interval for μ is
Transcript text: A sample of size $n=38$ is drawn from a population whose standard deviation is $\sigma=44$. Find the margin of error for a $90 \%$ confidence interval for $\mu$. Round the answer to at least three decimal places. The margin of error for a $90 \%$ confidence interval for $\mu$ is $\square$
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Solution

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Solution Steps

Step 1: Determine the Z-Score

For a 90% confidence interval, the Z-score corresponding to the critical value is:

\[ Z = 1.645 \]

Step 2: Calculate the Margin of Error

The formula for the margin of error \(E\) is given by:

\[ E = \frac{Z \times \sigma}{\sqrt{n}} \]

Substituting the known values:

  • \(Z = 1.645\)
  • \(\sigma = 44\)
  • \(n = 38\)

We can compute the margin of error as follows:

\[ E = \frac{1.645 \times 44}{\sqrt{38}} \]

Calculating the denominator:

\[ \sqrt{38} \approx 6.164 \]

Now substituting back into the equation:

\[ E = \frac{1.645 \times 44}{6.164} \approx \frac{72.38}{6.164} \approx 11.741 \]

Final Answer

The margin of error for a 90% confidence interval is:

\[ \boxed{11.741} \]

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