Questions: Practice Exercises Balance the following single replacement reactions. 1. Al+Fe3O4 → Al2O3+Fe 2. Zn+HCl → H2+ZnCl2 3. Fe+CuSO4 → FeSO4+Cu 4. Cu+AgNO3 → Ag+Cu(NO3)2 5. Na 6. Al+H2O Pb(NO3)2 → NaOH+Al(NO3)2+H2 Double Replacement CaCO3+2 HCl → CaCl2+H2CO3 Double Replacement Ca(OH)2+2 H3PO4 → Ca3(PO4)2+H2O

Practice Exercises Balance the following single replacement reactions. 1. Al+Fe3O4 → Al2O3+Fe 2. Zn+HCl → H2+ZnCl2 3. Fe+CuSO4 → FeSO4+Cu 4. Cu+AgNO3 → Ag+Cu(NO3)2 5. Na 6. Al+H2O Pb(NO3)2 → NaOH+Al(NO3)2+H2 Double Replacement CaCO3+2 HCl → CaCl2+H2CO3 Double Replacement Ca(OH)2+2 H3PO4 → Ca3(PO4)2+H2O
Transcript text: Practice Exercises Balance the following single replacement reactions. 1. $\mathrm{Al}+\mathrm{Fe}_{3} \mathrm{O}_{4} \rightarrow \mathrm{Al}_{2} \mathrm{O}_{3}+\mathrm{Fe}$ 2. $\mathrm{Zn}+\mathrm{HCl} \rightarrow \mathrm{H}_{2}+\mathrm{ZnCl}_{2}$ 3. $\mathrm{Fe}+\mathrm{CuSO}_{4} \rightarrow \mathrm{FeSO}_{4}+\mathrm{Cu}$ 4. $\mathrm{Cu}+\mathrm{AgNO}_{3} \rightarrow \mathrm{Ag}+\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}$ 5. $\mathrm{Na}$ 6. $\mathrm{Al}+\mathrm{H}_{2} \mathrm{O} \mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2} \rightarrow \mathrm{NaOH}+\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{2}+\mathrm{H}_{2}$ Double Replacement $\mathrm{CaCO}_{3}+2 \mathrm{HCl} \rightarrow \mathrm{CaCl}_{2}+\mathrm{H}_{2} \mathrm{CO}_{3}$ Double Replacement $\mathrm{Ca}(\mathrm{OH})_{2}+2 \mathrm{H}_{3} \mathrm{PO}_{4} \rightarrow \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}+\mathrm{H}_{2} \mathrm{O}$
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Solution

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Solution Steps

Step 1: Balance the Reaction for Aluminum and Iron(III) Oxide

The unbalanced reaction is: \[ \mathrm{Al} + \mathrm{Fe}_3\mathrm{O}_4 \rightarrow \mathrm{Al}_2\mathrm{O}_3 + \mathrm{Fe} \]

First, balance the aluminum (Al) atoms: \[ 4\mathrm{Al} + \mathrm{Fe}_3\mathrm{O}_4 \rightarrow 2\mathrm{Al}_2\mathrm{O}_3 + \mathrm{Fe} \]

Next, balance the iron (Fe) atoms: \[ 4\mathrm{Al} + \mathrm{Fe}_3\mathrm{O}_4 \rightarrow 2\mathrm{Al}_2\mathrm{O}_3 + 3\mathrm{Fe} \]

Step 2: Balance the Reaction for Zinc and Hydrochloric Acid

The unbalanced reaction is: \[ \mathrm{Zn} + \mathrm{HCl} \rightarrow \mathrm{H}_2 + \mathrm{ZnCl}_2 \]

First, balance the chlorine (Cl) atoms: \[ \mathrm{Zn} + 2\mathrm{HCl} \rightarrow \mathrm{H}_2 + \mathrm{ZnCl}_2 \]

Next, check the hydrogen (H) atoms, which are already balanced.

Step 3: Balance the Reaction for Iron and Copper(II) Sulfate

The unbalanced reaction is: \[ \mathrm{Fe} + \mathrm{CuSO}_4 \rightarrow \mathrm{FeSO}_4 + \mathrm{Cu} \]

This reaction is already balanced as written.

Final Answer

  1. \(\boxed{4\mathrm{Al} + \mathrm{Fe}_3\mathrm{O}_4 \rightarrow 2\mathrm{Al}_2\mathrm{O}_3 + 3\mathrm{Fe}}\)
  2. \(\boxed{\mathrm{Zn} + 2\mathrm{HCl} \rightarrow \mathrm{H}_2 + \mathrm{ZnCl}_2}\)
  3. \(\boxed{\mathrm{Fe} + \mathrm{CuSO}_4 \rightarrow \mathrm{FeSO}_4 + \mathrm{Cu}}\)
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