Questions: 5. Calculate the volume of an acetone sample with a mass of 7.89 g. Show your work. 0.79 g / mL x 7.89 6. A group of glass beads with a mass of 29.36 g is placed into a graduated cylinder containing 10.0 mL water. The water level rises to 21.7 mL. Calculate the density of the beads. Show your work.

Solution Steps

• Mass of acetone: \(7.89 \, \text{g}\)
• Density of acetone: \(0.79 \, \text{g/mL}\)

The formula for density is: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \] Rearrange to solve for volume: \[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \]

Substitute the given values into the formula: \[ \text{Volume} = \frac{7.89 \, \text{g}}{0.79 \, \text{g/mL}} \]

\[ \text{Volume} = 10 \, \text{mL} \]

• Mass of glass beads: \(29.36 \, \text{g}\)
• Initial water volume: \(10.0 \, \text{mL}\)
• Final water volume: \(21.7 \, \text{mL}\)

The volume of the beads is the difference between the final and initial water volumes: \[ \text{Volume of beads} = 21.7 \, \text{mL} - 10.0 \, \text{mL} = 11.7 \, \text{mL} \]

The formula for density is: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

Substitute the given values into the formula: \[ \text{Density} = \frac{29.36 \, \text{g}}{11.7 \, \text{mL}} \]

\[ \text{Density} \approx 2.51 \, \text{g/mL} \]

Final Answer