Questions: Part A In the reaction inside Flask 3, you observed that this was the neutralization reaction: HNO3 + NaOH -> NaNO3 + H2O What is the conjugate acid in this reaction? View Available Hint(s) H2O NaNO3 NaOH HNO3

Part A In the reaction inside Flask 3, you observed that this was the neutralization reaction: HNO3 + NaOH -> NaNO3 + H2O What is the conjugate acid in this reaction? View Available Hint(s) H2O NaNO3 NaOH HNO3
Transcript text: Part A In the reaction inside Flask 3, you observed that this was the neutralization reaction: \[ \mathrm{HNO}_{3}+\mathrm{NaOH} \rightarrow \mathrm{NaNO}_{3}+\mathrm{H}_{2} \mathrm{O} \] What is the conjugate acid in this reaction? View Available Hint(s) $\mathrm{H}_{2} \mathrm{O}$ $\mathrm{NaNO}_{3}$ NaOH $\mathrm{HNO}_{3}$ Submit
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Solution

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Solution Steps

Step 1: Identify the Acid and Base

In the given reaction: \[ \mathrm{HNO}_{3} + \mathrm{NaOH} \rightarrow \mathrm{NaNO}_{3} + \mathrm{H}_{2} \mathrm{O} \] we need to identify the acid and the base. Here, \(\mathrm{HNO}_{3}\) (nitric acid) is the acid, and \(\mathrm{NaOH}\) (sodium hydroxide) is the base.

Step 2: Determine the Conjugate Acid-Base Pairs

In a neutralization reaction, the acid (\(\mathrm{HNO}_{3}\)) donates a proton (H\(^+\)) to the base (\(\mathrm{NaOH}\)). The products are \(\mathrm{NaNO}_{3}\) (sodium nitrate) and \(\mathrm{H}_{2}\mathrm{O}\) (water).

Step 3: Identify the Conjugate Acid

The conjugate acid is formed when the base accepts a proton. In this reaction, \(\mathrm{NaOH}\) accepts a proton to form \(\mathrm{H}_{2}\mathrm{O}\). Therefore, \(\mathrm{H}_{2}\mathrm{O}\) is the conjugate acid.

Final Answer

\(\boxed{\mathrm{H}_{2}\mathrm{O}}\)

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