The diagonals of the rhombus are formed by the two intersecting lines. Each diagonal is split in half where they intersect. One diagonal has length $6\,\text{ft} + 6\,\text{ft} = 12\,\text{ft}$, and the other has length $15\,\text{ft} + 15\,\text{ft} = 30\,\text{ft}$.
The area of a rhombus is given by the formula:
Area $= \frac{1}{2} \times d_1 \times d_2$, where $d_1$ and $d_2$ are the lengths of the diagonals.
In our case, $d_1 = 12\,\text{ft}$ and $d_2 = 30\,\text{ft}$.
Area $= \frac{1}{2} \times 12\,\text{ft} \times 30\,\text{ft} = 180\,\text{ft}^2$.