Questions: Find the rectangular form of the complex number (z). Use whatever identities are necessary to find the exact values. The exercise should be worked out without the aid of a calculator.
(z=3 operatornamecisleft(frac3 pi4right)=a+b i text where )
(a=square)
(b=square)
Transcript text: Find the rectangular form of the complex number $z$. Use whatever identities are necessary to find the exact values. The exercise should be worked out without the aid of a calculator.
\[
\begin{array}{l}
z=3 \operatorname{cis}\left(\frac{3 \pi}{4}\right)=a+b i \text { where } \\
a=\square \\
b=\square
\end{array}
\]
Solution
Solution Steps
To convert the complex number from polar form to rectangular form, we use the identity \( z = r \operatorname{cis}(\theta) = r(\cos(\theta) + i\sin(\theta)) \). Here, \( r = 3 \) and \( \theta = \frac{3\pi}{4} \). We need to calculate \( a = r \cos(\theta) \) and \( b = r \sin(\theta) \).
Step 1: Convert Polar to Rectangular Form
We start with the complex number in polar form given by \( z = 3 \operatorname{cis}\left(\frac{3\pi}{4}\right) \). Using the identity \( z = r(\cos(\theta) + i\sin(\theta)) \), we identify \( r = 3 \) and \( \theta = \frac{3\pi}{4} \).
Step 2: Calculate \( a \) and \( b \)
Next, we calculate the rectangular components \( a \) and \( b \):
\[
a = r \cos\left(\frac{3\pi}{4}\right) = 3 \cos\left(\frac{3\pi}{4}\right) = 3 \left(-\frac{\sqrt{2}}{2}\right) = -\frac{3\sqrt{2}}{2}
\]
\[
b = r \sin\left(\frac{3\pi}{4}\right) = 3 \sin\left(\frac{3\pi}{4}\right) = 3 \left(\frac{\sqrt{2}}{2}\right) = \frac{3\sqrt{2}}{2}
\]
Step 3: Final Rectangular Form
Thus, the rectangular form of the complex number \( z \) is:
\[
z = a + bi = -\frac{3\sqrt{2}}{2} + \frac{3\sqrt{2}}{2} i
\]