Questions: The functions (f) and (g) are defined as follows.
(f(x)=3 x^2-3 x) and (g(x)=4 x+4).
Find (f(-2)) and (g(-3)). Simplify your answers as much as possible.
(f(-2)=)
(g(-3)=)
Transcript text: The functions $f$ and $g$ are defined as follows.
\[
f(x)=3 x^{2}-3 x \quad g(x)=4 x+4
\]
Find $f(-2)$ and $g(-3)$
Simplify your answers as much as possible.
\[
f(-2)=
\]
$\square$
\[
g(-3)=
\]
$\square$
Solution
Solution Steps
To find \( f(-2) \), substitute \(-2\) into the function \( f(x) = 3x^2 - 3x \) and evaluate. Similarly, to find \( g(-3) \), substitute \(-3\) into the function \( g(x) = 4x + 4 \) and evaluate.
Step 1: Evaluate \( f(-2) \)
To find \( f(-2) \), we substitute \(-2\) into the function \( f(x) = 3x^2 - 3x \):
\[
f(-2) = 3(-2)^2 - 3(-2) = 3(4) + 6 = 12 + 6 = 18
\]
Step 2: Evaluate \( g(-3) \)
Next, we find \( g(-3) \) by substituting \(-3\) into the function \( g(x) = 4x + 4 \):
\[
g(-3) = 4(-3) + 4 = -12 + 4 = -8
\]
Final Answer
Thus, the results are:
\[
f(-2) = 18
\]
\[
g(-3) = -8
\]
The final answers are:
\[
\boxed{f(-2) = 18}
\]
\[
\boxed{g(-3) = -8}
\]