Questions: The area of the shape is □ mm².

Solution Steps

The given shape can be divided into two rectangles. Let's label them as Rectangle A (top part) and Rectangle B (bottom part).

Rectangle A has a length of 12 mm and a height of 2 mm. \[ \text{Area of Rectangle A} = \text{length} \times \text{height} = 12 \, \text{mm} \times 2 \, \text{mm} = 24 \, \text{mm}^2 \]

Rectangle B has a length of 4.3 mm and a height of 9.1 mm. \[ \text{Area of Rectangle B} = \text{length} \times \text{height} = 4.3 \, \text{mm} \times 9.1 \, \text{mm} = 39.13 \, \text{mm}^2 \]

The overlapping area (small rectangle) has a length of 8 mm and a height of 2 mm. \[ \text{Overlapping Area} = \text{length} \times \text{height} = 8 \, \text{mm} \times 2 \, \text{mm} = 16 \, \text{mm}^2 \]

Add the areas of Rectangle A and Rectangle B, then subtract the overlapping area. \[ \text{Total Area} = \text{Area of Rectangle A} + \text{Area of Rectangle B} - \text{Overlapping Area} \] \[ \text{Total Area} = 24 \, \text{mm}^2 + 39.13 \, \text{mm}^2 - 16 \, \text{mm}^2 = 47.13 \, \text{mm}^2 \]

Final Answer