Questions: Solve the absolute value equation.
𝑥²−8=5
Transcript text: Solve the absolute value equation.
$\left|x^{2}-8\right|=5$
Solution
Solution Steps
To solve the absolute value equation \(|x^2 - 8| = 5\), we need to consider two separate cases: \(x^2 - 8 = 5\) and \(x^2 - 8 = -5\). Solving these equations will give us the possible values of \(x\).
Step 1: Solve the First Case
We start with the equation from the absolute value:
\[
x^2 - 8 = 5
\]
Rearranging gives:
\[
x^2 = 13
\]
Taking the square root of both sides, we find:
\[
x = \pm \sqrt{13} \approx \pm 3.6056
\]
Step 2: Solve the Second Case
Next, we consider the second case:
\[
x^2 - 8 = -5
\]
Rearranging gives:
\[
x^2 = 3
\]
Taking the square root of both sides, we find:
\[
x = \pm \sqrt{3} \approx \pm 1.7321
\]
Step 3: Compile All Solutions
Combining the solutions from both cases, we have:
\[
x \approx 3.6056, -3.6056, 1.7321, -1.7321
\]
Final Answer
The complete set of solutions is:
\[
\boxed{x \approx \{3.6056, -3.6056, 1.7321, -1.7321\}}
\]