We start with the expression \((2y - 3)^{2}\).
Using the formula for the square of a binomial, we expand the expression: \[ (2y - 3)^{2} = (2y)^{2} - 2 \cdot (2y) \cdot 3 + 3^{2} \]
Calculating each term, we have: \[ (2y)^{2} = 4y^{2}, \quad -2 \cdot (2y) \cdot 3 = -12y, \quad \text{and} \quad 3^{2} = 9 \] Combining these results gives us: \[ (2y - 3)^{2} = 4y^{2} - 12y + 9 \]
\(\boxed{4y^{2} - 12y + 9}\)
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