Questions: A 2.80 kg mass is dropped from a height of 4.50 m. What is the potential energy of the mass when it reaches the ground? PE=[?] J

A 2.80 kg mass is dropped from a height of 4.50 m.

What is the potential energy of the mass when it reaches the ground?
PE=[?] J
Transcript text: A 2.80 kg mass is dropped from a height of 4.50 m . What is the potential energy of the mass when it reaches the ground? \[ P E=[?] \mathrm{J} \]
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Solution

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Solution Steps

Step 1: Identify the formula for potential energy

The potential energy (PEPE) of an object at a height (hh) is given by the formula: PE=mgh PE = mgh where:

  • mm is the mass of the object,
  • gg is the acceleration due to gravity (9.8m/s29.8 \, \text{m/s}^2),
  • hh is the height from which the object is dropped.
Step 2: Substitute the given values

Given:

  • m=2.80kgm = 2.80 \, \text{kg},
  • h=4.50mh = 4.50 \, \text{m},
  • g=9.8m/s2g = 9.8 \, \text{m/s}^2.

Substitute these values into the formula: PE=2.80×9.8×4.50 PE = 2.80 \times 9.8 \times 4.50

Step 3: Calculate the potential energy

Perform the multiplication: PE=2.80×9.8×4.50=123.48J PE = 2.80 \times 9.8 \times 4.50 = 123.48 \, \text{J}

Thus, the potential energy of the mass when it reaches the ground is 123.48J123.48 \, \text{J}.

Final Answer

123.48J\boxed{123.48 \, \text{J}}

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