To solve the logarithmic equation \(\log_{3}(x^9) = -2\), we can convert it to its exponential form. The equation \(\log_{b}(a) = c\) is equivalent to \(b^c = a\). Applying this to the given equation, we get \(3^{-2} = x^9\). We then solve for \(x\) by taking the ninth root of both sides.
Step 1: Convert to Exponential Form
We start with the logarithmic equation:
\[
\log_{3}(x^9) = -2
\]
Converting this to exponential form gives us:
\[
3^{-2} = x^9
\]
To find \(x\), we take the ninth root of both sides:
\[
x = \left(\frac{1}{9}\right)^{\frac{1}{9}} = 9^{-\frac{1}{9}}
\]
Calculating this gives us approximately:
\[
x \approx 0.7834
\]