Questions: Question 11 2 Points If a student scored 87 points on a test where the mean score was 81 and the standard deviation was 1.7. The student's z score is - (A) 3.56 (B) 4.12 (C) 3.87 (D) 3.53

Solution Steps

To find the student's z-score, we use the formula:

\[ z = \frac{X - \mu}{\sigma} \]

where:

• \( X = 87 \) (the student's score),
• \( \mu = 81 \) (the mean score),
• \( \sigma = 1.7 \) (the standard deviation).

Substituting the values into the formula gives:

\[ z = \frac{87 - 81}{1.7} = \frac{6}{1.7} \approx 3.5294 \]

Rounding to two decimal places, we find:

\[ z \approx 3.53 \]

Final Answer