Questions: Use the following function to answer parts a through c.
f(x) = x^3 + 6x^2 - 28x - 33
a. List all rational zeros that are possible according to the Rational Zero Theorem.
(Type an integer or a simplified fraction. Use a comma to separate answers as needed. Type each answer only once.)
b. Use synthetic division to test several possible rational zeros in order to identify one actual zero.
One rational zero of the given function is
(Simplify your answer.)
c. Use the zero from part (b) to find all the zeros of the polynomial function.
The zeros of the function are
(Simplify your answer. Use a comma to separate answers as needed. Type an integer or decimal rounded to three decimal places as needed.)
Transcript text: Use the following function to answer parts a through c.
\[
f(x)=x^{3}+6 x^{2}-28 x-33
\]
a. List all rational zeros that are possible according to the Rational Zero Theorem.
(Type an integer or a simplified fraction. Use a comma to separate answers as needed. Type each answer only once.)
b. Use synthetic division to test several possible rational zeros in order to identify one actual zero.
One rational zero of the given function is $\square$
(Simplify your answer.)
c. Use the zero from part (b) to find all the zeros of the polynomial function.
The zeros of the function are $\square$
(Simplify your answer. Use a comma to separate answers as needed. Type an integer or decimal rounded to three decimal places as needed.)
Solution
Solution Steps
Step 1: List Possible Rational Zeros
The possible rational zeros are of the form \(\pm \frac{p}{q}\), where \(p\) is a factor of the constant term \(a_0\) and \(q\) is a factor of the leading coefficient \(a_n\).
Given that \(a_0 = -33\) and \(a_n = 1\), the possible rational zeros are: [Fraction(-33, 1), Fraction(-11, 1), Fraction(-3, 1), Fraction(-1, 1), Fraction(1, 1), Fraction(3, 1), Fraction(11, 1), Fraction(33, 1)]
Step 2: Test Possible Zeros
Using synthetic division or the remainder theorem, we test each possible zero. The actual zeros are those for which \(f(r) = 0\).
The actual rational zeros are: [Fraction(-1, 1)]