Questions: Find the 29th term.
20, 14, 8, 2, -4, ...
29th term = [?]
1st term + common difference(desired term -1)
Transcript text: Find the 29th term.
\[
\begin{array}{c}
20,14,8,2,-4, \ldots \\
29^{\text {th }} \text { term }=[?]
\end{array}
\]
1st term + common difference(desired term -1 )
Solution
Solution Steps
Step 1: Identify the Sequence
The given arithmetic sequence is \( 20, 14, 8, 2, -4, \ldots \). The first term \( a_1 \) is \( 20 \) and the common difference \( d \) can be calculated as:
\[
d = 14 - 20 = -6
\]
Step 2: Apply the Formula for the nth Term
To find the 29th term \( a_{29} \) of the sequence, we use the formula for the nth term of an arithmetic sequence:
\[
a_n = a_1 + (n - 1) \cdot d
\]
Substituting the known values:
\[
a_{29} = 20 + (29 - 1) \cdot (-6)
\]
Step 3: Calculate the 29th Term
Now, we simplify the expression:
\[
a_{29} = 20 + 28 \cdot (-6) = 20 - 168 = -148
\]
Final Answer
The 29th term of the sequence is \\(\boxed{-148}\\).