Questions: A field biologist examined the sex ratio at birth of the lesser snow geese. A random sample of nests containing four eggs was taken. For each egg resulting in a live gosling, the laying order and the gender of the gosling were recorded. Of the 46 successfully hatched first eggs, 25 were male.
Are the conditions met to calculate a confidence interval for the proportion of successfully hatched first eggs that are male? Choose the most complete answer.
Yes: a random sample was taken, and both n(p-hat) ≥ 10 and n(1-(p-hat)) ≥ 10
Yes: a random sample was taken, and both np ≥ 10 and n(1-p) ≥ 10
No: a random sample was taken, but the n(p-hat) ≥ 10 and n(1-(p-hat)) ≥ 10 condition was not met
No: a random sample was taken, but the np ≥ 10 and n(1-p) ≥ 10 condition was not met
Transcript text: snowGeese STEM
A field biologist examined the sex ratio at birth of the lesser snow geese. A random sample of nests containing four eggs was taken. For each egg resulting in a live gosling, the laying order and the gender of the gosling were recorded. Of the 46 successfully hatched first eggs, 25 were male.
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Multiple
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Choice point
Are the conditions met to calculate a confidence interval for the proportion of successfully hatched first eggs that are male? Choose the most complete answer.
Yes: a random sample was taken, and both $n \hat{p} \geq 10$ and $n(1-\hat{p}) \geq 10$
Yes: a random sample was taken, and both $n p \geq 10$ and $n(1-p) \geq 10$
No: a random sample was taken, but the $n \hat{p} \geq 10$ and $n(1-\hat{p}) \geq 10$ condition was not met
No: a random sample was taken, but the $n p \geq 10$ and $n(1-p) \geq 10$ condition was not met
Solution
Solution Steps
Step 1: Calculate $\hat{p}$
The sample proportion of male goslings is $\hat{p} = \frac{25}{46} \approx 0.543$
Step 2: Check the first condition
The first condition is $n\hat{p} \ge 10$. In this case, $n\hat{p} = 46 \times \frac{25}{46} = 25 \ge 10$. So, the first condition is met.
Step 3: Check the second condition
The second condition is $n(1-\hat{p}) \ge 10$. Here, $n(1-\hat{p}) = 46 \times (1 - \frac{25}{46}) = 46 - 25 = 21 \ge 10$. Thus, the second condition is also met.
Final Answer:
The correct answer is: "Yes: a random sample was taken, and both $n\hat{p} \ge 10$ and $n(1-\hat{p}) \ge 10$".