Questions: Calculate the monthly payment by table lookup and formula. (Answers will not be exact due to rounding of percents in table lookup.). (Use 13% for table lookup.). (Use the loan amortization table) Note: Round your answers to the nearest cent.

Calculate the monthly payment by table lookup and formula. (Answers will not be exact due to rounding of percents in table lookup.). (Use 13% for table lookup.). (Use the loan amortization table)
Note: Round your answers to the nearest cent.
Transcript text: Calculate the monthly payment by table lookup and formula. (Answers will not be exact due to rounding of percents in table lookup.). (Use 13% for table lookup.). (Use the loan amortization table) Note: Round your answers to the nearest cent.
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Solution

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Solution Steps

To calculate the monthly payment for a loan, we can use the loan amortization formula. The formula for the monthly payment \( M \) is given by:

\[ M = \frac{P \cdot r \cdot (1 + r)^n}{(1 + r)^n - 1} \]

where:

  • \( P \) is the principal loan amount,
  • \( r \) is the monthly interest rate (annual rate divided by 12),
  • \( n \) is the total number of payments (loan term in years multiplied by 12).

For the table lookup, you would typically use a pre-calculated table based on the interest rate and loan term, but since we don't have the table here, we'll focus on the formula calculation.

Step 1: Calculate Monthly Payment Using the Formula

To find the monthly payment \( M \) for a loan, we use the formula:

\[ M = \frac{P \cdot r \cdot (1 + r)^n}{(1 + r)^n - 1} \]

where:

  • \( P = 10000 \) (principal amount),
  • \( r = \frac{13}{100 \cdot 12} = 0.0108333 \) (monthly interest rate),
  • \( n = 5 \cdot 12 = 60 \) (total number of payments).
Step 2: Substitute Values into the Formula

Substituting the values into the formula gives:

\[ M = \frac{10000 \cdot 0.0108333 \cdot (1 + 0.0108333)^{60}}{(1 + 0.0108333)^{60} - 1} \]

Step 3: Calculate the Monthly Payment

After performing the calculations, we find:

\[ M \approx 227.53 \]

Final Answer

The monthly payment is approximately \\(\boxed{227.53}\\).

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