Questions: Based on molecular structure, arrange the following binary compounds in order of decreasing acid strength. Rank compounds from strongest to weakest. To rank items as equivalent, overlap them. NaH H2S H2Te HI

Based on molecular structure, arrange the following binary compounds in order of decreasing acid strength.
Rank compounds from strongest to weakest. To rank items as equivalent, overlap them.
NaH
H2S
H2Te
HI
Transcript text: Based on molecular structure, arrange the following binary compounds in order of decreasing acid strength. Rank compounds from strongest to weakest. To rank items as equivalent, overlap them. NaH $\mathrm{H}_{2} \mathrm{~S}$ $\mathrm{H}_{2} \mathrm{Te}$ HI
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Solution

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Solution Steps

Step 1: Understanding Acid Strength in Binary Compounds

Acid strength in binary compounds is influenced by the bond strength between hydrogen and the other element, as well as the electronegativity of the other element. Generally, for binary acids (HX), the acid strength increases with the size of the halogen or chalcogen atom because the bond strength decreases, making it easier for the hydrogen ion to dissociate.

Step 2: Analyzing the Given Compounds

The compounds given are NaH, \(\mathrm{H}_{2} \mathrm{~S}\), \(\mathrm{H}_{2} \mathrm{Te}\), and HI.

  • NaH: Sodium hydride is not an acid; it is a strong base because it contains the hydride ion (\(\mathrm{H}^-\)).
  • \(\mathrm{H}_{2} \mathrm{~S}\) and \(\mathrm{H}_{2} \mathrm{Te}\): These are hydrides of sulfur and tellurium, respectively. As we move down the group in the periodic table, the size of the atom increases, and the bond strength decreases, making \(\mathrm{H}_{2} \mathrm{Te}\) a stronger acid than \(\mathrm{H}_{2} \mathrm{~S}\).
  • HI: Hydroiodic acid is a strong acid because iodine is large, and the H-I bond is weak, allowing easy dissociation of the hydrogen ion.
Step 3: Ranking the Compounds

Based on the analysis, the order of acid strength from strongest to weakest is:

  1. HI (strongest)
  2. \(\mathrm{H}_{2} \mathrm{Te}\)
  3. \(\mathrm{H}_{2} \mathrm{~S}\)
  4. NaH (weakest, not an acid)

Final Answer

\[ \boxed{\text{HI} > \mathrm{H}_{2} \mathrm{Te} > \mathrm{H}_{2} \mathrm{S} > \text{NaH}} \]

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