Questions: PCl3 Trigonal pyramidal ✓ CH2S Bent CO2 ☐ SeF2 ☐

PCl3 Trigonal pyramidal ✓ CH2S Bent CO2 ☐ SeF2 ☐
Transcript text: PCl3 Trigonal pyramidal ✓ CH2S Bent CO2 ☐ SeF2 ☐
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Solution

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Solution Steps

Step 1: Determine the Molecular Geometry of $\mathrm{CO}_{2}$

The molecular geometry of $\mathrm{CO}_{2}$ (carbon dioxide) can be determined by considering its Lewis structure and the VSEPR (Valence Shell Electron Pair Repulsion) theory. $\mathrm{CO}_{2}$ has a linear structure because the central carbon atom forms double bonds with each of the two oxygen atoms, and there are no lone pairs on the carbon atom.

Step 2: Determine the Molecular Geometry of $\mathrm{SeF}_{2}$

The molecular geometry of $\mathrm{SeF}_{2}$ (selenium difluoride) can be determined by considering its Lewis structure and the VSEPR theory. $\mathrm{SeF}_{2}$ has a bent structure because the central selenium atom has two bonding pairs and two lone pairs of electrons, leading to a bent shape similar to that of water ($\mathrm{H}_2\mathrm{O}$).

Final Answer

  • $\mathrm{CO}_{2}$: Linear
  • $\mathrm{SeF}_{2}$: Bent

\[ \boxed{\text{Linear, Bent}} \]

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